80gram Na oH (Ar Na=23,Ar O = 16,Ar H =1 berapakah mol tersebut

Rumus !
Mr NaOh = Ar N + Ar O + Ar H
Mr NaOH = 23 + 16 + 1
Mr NaOH = 40


mol = gram/Mr
mol = 80/40
mol = ② mol

Semoga membantu

Massa = 80 gram
Mr NaOH
= Ar Na + Ar O + Ar H
= 23 + 16 + 1
= 40

n NaOH
= massa / Mr
= 80 / 40
= 2 mol.