Matematika

Pertanyaan

Tanpa menggunakan tabel trigonometri maupun kalkulator, hitung:
sin² 6° + sin² 42° + sin² 66° + sin² 78° = ...

1 Jawaban

  • →Sin²6° + sin²42° + Sin²66° + Sin²78°
    =[Sin²66 + sin²6] +
    [ sin²78+sin²42]
    =[2sin²½(66+6)cos²½(66-6)] + [2sin²½(78+42)cos²½(78-42)]
    =[2sin²36°cos²30° ] + [2sin²60°cos²36°]
    = 2sin²36° (½√3)² + 2(½√3)cos²(36)°
    = 2sin²36°(3/4)+ 2(3/4)cos²(36)°
    = (3/2)sin²36°+ (3/2)cos²(36)°
    = (3/2)( sin²36° + cos²36°)
    = (3/2)(1)
    =3/2
    jadi hasil akhirnya 3/2

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