No 49 tentang limit tolong dibantu yaa :)

[tex]\lim_{x \to \infty} \frac{(3x+2) + \sqrt{4x^{2}+7x+1}}{(5x+1)- \sqrt[3]{27x^{3}+2x+9} } \\ = \lim_{x \to \infty} \frac{\frac{(3x+2) + \sqrt{4x^{2}+7x+1}}{x}}{\frac{(5x+1)- \sqrt[3]{27x^{3}+2x+9}}{x}} \\ = \lim_{x \to \infty} \frac{\frac{3x}{x}+\frac{2}{x}+\sqrt{\frac{4x^{2}}{x^{2}}+\frac{7x}{x^{2}}+\frac{1}{x^{2}}}}{\frac{5x}{x}+\frac{1}{x}-\sqrt[3]{\frac{27x^{3}}{x^{3}}+\frac{2x}{x^{3}}+\frac{9}{x^{3}}}} \\[/tex]

[tex]= \frac{3+\frac{2}{\infty}+\sqrt{4+\frac{7}{\infty}+\frac{1}{\infty^{2}}}}{5+\frac{1}{\infty}-\sqrt[3]{27+\frac{2}{\infty^{2}}+\frac{9}{\infty^{3}}}} \\ = \frac{3 + 0 + \sqrt{4+0+0}}{5+0-\sqrt[3]{27+0+0}} \\ =\frac{3+2}{5-3} \\ =\frac{5}{2} [/tex]

Mohon diteliti kembali.
Jika ada yang salah atau tidak paham, mohon segera komentar.