Mnta bantuannya y Kak..?!?!

Misal garis k tersebut adalah y = mx + c
k melalui (1, -8) => -8 = m(1) + c => c = -m - 8
y = mx + c => y = mx - m - 8
Garis k menyinggung y = x^2 di kuadran2 di titik (a, a^2)
y = y
x^2 = mx - m - 8
x^2 - mx + m + 8 = 0
Karena menyinggung D = 0
b^2 - 4ac = 0
(-m)^2 - 4(1)(m + 8) = 0
m^2 - 4m - 32 = 0
(m - 8)(m + 4) = 0
m = 8 atau m = -4

Jika m = 8
x^2 - mx + m + 8 = 0
x^2 - 8x + 8 + 8 = 0
x^2 - 8x + 16 = 0
(x - 4)(x - 4) = 0
x = 4 ====> dikuadran 1

Jika m = -4
x^2 - mx + m + 8 = 0
x^2 - (-4)x + (-4) + 8 = 0
x^2 + 4x + 4 = 0
(x + 2)(x + 2) = 0
x = -2 =========> dikuadran 2
y = x^2 = (-2)^2 = 4

Jadi a = -2