Ph dari 50 ml ch3cooh 0,2m (ka=10^-5) dan50 ml naoh 0,2 m

[H+] = akar (Ka × Ma × valensi asam)
[H+] = akar (10^-5 × 2×10^-1 × 1)
[H+] = akar (2 × 10^-6)
[H+] = 1.4 × 10^-3
pH = 3-log 1.4

[OH-] = Mb × b
[OH-] = 2×10^-1 × 1
pOH = 1-log2
pH = 13 + log 2

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