sebuah prisma dengan alas berbentuk belah ketupat mempunyai keliling 52cm dan panjang salah satu diagonalnya alasnya 10cm jika luas selumbung prisma 1.040cm per

s = 52÷4 = 13 cm
d1 = 10 cm
d2² = 13²-5² × 2
d2² = 169-25 × 2
d2² = 144 × 2
d2 = √144 × 2
d2 = 12 × 2
d2 = 24 cm

lp prisma = 2×L alas + k alas × t prisma = 1.040 cm²
lp prisma = 2×d1×d2/2 + k alas × t prisma = 1.040
lp prisma = 2×10×24/2 + 52 × t prisma = 1.040
lp prisma = 240 + 52 × t prisma = 1.040
lp prisma = 52 × t prisma = 1.040 - 240
lp prisma = 52 × t prisma = 800
lp prisma = t prisma = 800/52
lp prisma = t prisma = 15,38461538 cm

v prisma = L alas × t prisma
v prisma = 120 × 15.38461538
v prisma = 1846,153846 cm³ atau jika disederhanakan 1846,15 cm³

mencari sisi belah ketupat
= 1/4 x keliling
= 1/4 x 52
= 13 cm

mencari diagonal 2
= 2 x √13² - (10/2)²
= 2 x √13² - 5²
= 2 x √169 - 25
= 2 x √144
= 2 x 12
= 24 cm

mencari tinggi prisma
= 1/4 x luas selubung x 1/sisi belah ketupat
= 1/4 x 1.040 x 1/13
= 260 x 1/13
= 20 cm

volume prisma belah ketupat
= luas alas x tinggi
= (1/2 x 10 x 24) x 20
= 120 x 20
= 2.400 cm³