Sin1050°+2cos(-240°)-sin(-30°)
Matematika
Harbi706
Pertanyaan
Sin1050°+2cos(-240°)-sin(-30°)
1 Jawaban
-
1. Jawaban Jawer17
sin(1050 - 2(360)) + 2 cos(240) - (-sin30)
= sin330 + 2 cos(180+60) + sin30
= sin(360 - 30) - 2 cos60 + sin30
= -sin30 - 2cos60 + sin30
= -2 cos60
= -2(1/2)
= -1