Hitunglah ph larutan CH3COOH 0.05 M dgn ka= 1,8×10-5
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Pertanyaan
Hitunglah ph larutan CH3COOH 0.05 M dgn ka= 1,8×10-5
1 Jawaban
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1. Jawaban Leli238
CH3COOH 0.05 (Ka=1,8 x 10-5)
asam lemah
[H+]= √Ka x Ma
= √18 x 10-6 x 5 x 10-2
= √90 x 10-8
= √9 x 10-7
= 3√10 . 10-4
ph = -log [H+]
= -log [3√10 . 10-4
ph = 4 - log 3√10