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Tentukan [tex]\int \sqrt{2x-1}d(2x-1)[/tex].

---- Bisa menggunakan integral biasa ----
misal 2x-1 = a
[tex]\int \sqrt{2x-1}d(2x-1) \\ \int \sqrt{a} \,da \\ = \int a^{\frac{1}{2}} \, da \\ = \frac{1}{\frac{1}{2}+1} a^{\frac{1}{2}+1} + C \\ = \frac{2}{3}a^{\frac{3}{2}} + C \\ = \frac{2}{3}a\sqrt{a} + C [/tex]

(Substitusi kembali)
[tex]= \frac{2}{3}(2x-1)\sqrt{2x-1} + C[/tex]

Mohon diteliti kembali.