SBMPTN

Pertanyaan

jika sin{2x+30drajat}=a dan sin{x + 45drajat}=b,maka sin{3x+75drajat}sin{x-15drajat}
a.{a-b}2
b.a2-b2
c.a2/akar2-b2/akar3
d.a2-2b/akar6+b2
e.2ab-1/akar6
mohon bantuanya poin lumayan

1 Jawaban

  • Rumus : cos 2x = 1 - 2 sin^2 x

    sin (2x + 30°) = a
    cos 2(2x + 30°) = 1 - 2 sin^2 (2x + 30°)
    cos (4x + 60°) = 1 - 2a^2

    sin (x + 45°) = b
    cos 2(x + 45°) = 1 - 2 sin^2 (x + 45°)
    cos (2x + 90°) = 1 - 2b^2

    Rumus : -2 sin A sin B = cos (A + B) - cos (A - B)
    sin A sin B = -1/2 (cos (A + B) - cos (A - B))
    sin (3x + 75°) sin (x - 15°)
    = -1/2 (cos ((3x + 75°) + (x - 15°)) - cos ((3x + 75°) - (x - 15°))
    = -1/2 (cos (4x + 60°) - cos (2x + 90°))
    = -1/2 ((1 - 2a^2) - (1 - 2b^2))
    = -1/2 (-2a^2 + 2b^2)
    = a^2 - b^2

    ^ = pangkat

Pertanyaan Lainnya