apabila 6,9 garam natrium nitrit dilarutkan kedalam air hingga volume 1 liter. berapakah ph larutan garam natrium nitrit tersebut jika Ka HN2 = 5x10^-5?
Kimia
xdchandra
Pertanyaan
apabila 6,9 garam natrium nitrit dilarutkan kedalam air hingga volume 1 liter. berapakah ph larutan garam natrium nitrit tersebut jika Ka HN2 = 5x10^-5?
1 Jawaban
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1. Jawaban sonyalindaa
[OH-] = akar (Kw/Ka x Molaritas garam x valensi)
[OH-] = akar [(10^-14/5×10^-5) × (6,9 × 1000 : 69 : 1000)]
[OH-] = akar (2 × 10^-10 × 10^-1)
[OH-] = akar (2 × 10^-11)
[OH-] = 1,4 × 10^-5,5
POH = 5,5 - log 1,4
pH = 8,5 + log 1,4
semoga membantu :) maaf jika ada kesalahan :)