Jika 4 (pangkat m) = 27,maka nilai 2(pangkat 2m+1) - 16(pangkat m+1) adalah

4^m = 27
2^2m = 27

2^(2m+1) - 16^(m+1)
=( 2^2m × 2^1 ) - 2^4(m+1)
= (27 × 2) - ( 2^4m × 2^4)
= 54 - (2^2m^2 × 16)
= 54 - (27^2 × 16)
= 54 - (729 × 16)
= 54 - 11664
= -11610