turunan pertama x^2+3x-1 dengan limit

2x + 3
Mungkin seperti maksudnya

[tex]f(x) = x^{2}+3x-1 \\ f(x+h) = (x+h)^{2}+3(x+h)-1 \\ f(x+h) = x^{2}+2xh+h^{2}+3x+3h-1 \\ \\ f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h} \\ f'(x) = \lim_{h \to 0} \frac{x^{2}+2xh+h^{2}+3x+3h-1 - (x^{2}+3x-1)}{h} \\ f'(x) = \lim_{h \to 0} \frac{2xh+h^{2}+3h}{h} \\ f'(x) = \lim_{h \to 0} \frac{h(2x+h+3))}{h} \\ f'(x) = \lim_{h \to 0} 2x + h + 3 \\ f'(x) = 2x + 3[/tex]