Tentukan akar akar dari persamaan kuadratX2-2x-24=0

x^2 - 2x - 24 = 0
x^2 - 6x + 4x - 24 = 0
x( x - 6) + 4(x - 6) = 0
(x + 4)(x - 6) = 0

x + 4 = 0
x = - 4

x - 6 = 0
x = 6

Akar akarnya = -4 dan 6

x² - 2x - 24 = 0
(x + 4) ( x - 6) = 0

himpunan penyelesaian :
x + 4 = 0
x = -4

x - 6 = 0
x = 6