Matematika

Pertanyaan

Diketahui f(x) 2x-2 , g(x) =akar4-x, h(x)=4x-xpangkat2.fungsi(f0g0h)(x)=

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  • Langsung aja y

    misal
    (fog)(x) = s(x)

    (fog)(x) = f{g(x)}

    = 2g(x) - 2
    = 2(√4 - x) - 2
    = 2√4 - 2x - 2

    (soh)(x) = s{h(x)}

    = 2√4 - 2h(x) - 2
    = 2√4 - 2(4x - x²) - 2
    = 2√4 - 8x + 2x² - 2
    = 2x² - 8x - 2√4 - 2
    = 2 (x² - 4x - √4 - 1)

    Semoga berguna +_+

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