Dik fungsi f:R->R dan g:R->R dengan f(x)= 2x+1 dan g(x) = 3xpangkat2+x-7 Rumus (gof) (x)=...

(gof)(x) = g(f(x))
= g(2x+1)
= 3(2x+1)^2 + (2x+1) - 7
= 3(4x^2 +4x+1) + 2x -6
= 12x^2 + 12x + 3 + 2x - 6
= 12x^2 + 14x -3
jadi (gof)(x) = 12x^2 + 14x - 3

g(f(x))=g(2x+1)
=3(2x+1)²+(2x+1)-7
=3(4x²+4x+1)+2x+1-7
=12x²+14x-3