integral 4x(2x²-5)^4 dx =

U=2x²-5
du/dx=4x
dx=du/4x
Integral 4x(u^4)du/4x
=integral u^4 du
=1/5 u^5 +c
=1/5 (2x²-5)^5 +c

∫ 4x (2x² - 5)⁴ dx
u = 2x² - 5
du / dx = 4x → dx = du / (4x)
= ∫ 4x u⁴ du / (4x)
= 1/5 u⁵ + C
= 1/5 (2x² - 5)⁵ + C