Matematika

Pertanyaan

1) limit x mendekati 0 x - sin x per x
2) limit x mendekati 0 sin x - sin 3x per sin x + sin 3x
3) limit x mendekati 0 x^3 + 3x^2 per 5 tan^2 2x
4) limit x mendekati 3 (x^3 - 2x^2 + x) cot^2 2(x-1)

1 Jawaban

  • limit trigonometri

    1. lim(x->0) (x - sin x ) /x
    = lim (x->0) x/x - sin x/x
    = 1 - 1
    = 0

    2. lim(x->0) (sin x - sin 3x)/(sin x + sin 3x)
    lim (x->0  ( sin x/x - sin 3x/x) / ( sin x /x  + sin 3x /x)
    = (1 - 3)/(1 +3)
    = -2/4
    = - 1/2

    3. lim(x->0) x³ + 3x²/ (5 tan² 2x)
    lim(x->0) x²(x+3) / 5 tan² 2x
    = lim(x->0)  [x²/(5 tan² 2x)] [ x+3]
    x= 0
    = [1/(5(2)²][(0+3)]
    = (1/20)(3)
    = 3/20.

    4. lim(x-> 3) (x³ -2x² +x) cot² 2(x-1)
    lim(x->3) x(x²-2x+1) / tan² 2(x-1)
    lim(x->3) x(x-1)² / tan² 2(x-1)
    lim(x->3) x {(x-1)²} / tan² 2(x-1)
    lim (x->3) x . lim(x->3) (x-1)²/ tan² 2(x-1)
    x = 3
    = 3 (1/2²)
    = 3(1/4)
    = 3/4

Pertanyaan Lainnya