Mm saya tlong bantuin ya

Jawaban seharusnya : f'(x) = 2x + 1/(2√x) => √x nya penyebut
f(x) = x^2 + √x
f'(x) = Lim [f(x + h) - f(x)] / h
= Lim [(x + h)^2 + √(x + h) - (x^2 + √x)] / h
= Lim [x^2 + 2xh + h^2 + √(x + h) - x^2 - √x] / h
= Lim [2xh + h^2 + √(x + h) - √x] / h
= Lim { [2xh + h^2]/h + [√(x + h) - √x]/h }
= Lim [2xh + h^2]/h + Lim [√(x + h) - √x]/h . (√(x + h) + √x)/(√(x + h) + √x)
= Lim h(2x + h) / h + Lim ((x + h) - x) / h(√x + h) + √x)
= Lim (2x + h) + Lim h / h(√(x + h) + √x)
= Lim (2x + h) + Lim 1/(√(x + h) + √x)
= (2x + 0) + 1/(√(x + 0) + √x)
= 2x + 1/(√x + √x)
= 2x + 1/(2√x)