Ka aq mau tanya hasil dari sin×:1+cos× +1+cos×:sin× thanks ka

Trigonometri
bentuk (a/b + b/a) = (a² +b²)/(ab)

(sin x)/(1+cos x)  + (1+cos x)/sinx =
= [(sin x )(sin x)  + (1+cos x)(1+cos x) ]/(sin x(1+cos x)
= [ sin² x + 1+ 2 cos x + cos² x] /  sin x (1+cos x)
= [ (sin² x+ cos² x) + 1 + 2 cos x] / sin x [ 1+cos x]
= [ 1 + 1 + 2cos x ] /  sin x [ 1 + cos x]
= [2 + 2 cos x] / sin x [ 1 + cos x]
= 2[1 +cos x] / sin x [1+cos x]
= 2/sin x
= 2 csc x
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