Diketahui 4x²+7x-1=0 maka persamaan kuadrat yang akar akarnya (p-2) dan (q-2) adalah

p + q = -b/a = -7/4
p × q = c/a = -1/4
persamaan baru
x² - {(p-2)+(q-2)}x + (p-2)(q-2) = 0
x² - (p+q-4)x + (pq-2(p+q)+4) = 0
x² - (-7/4 - 4)x + (-1/4 - 2(-7/4) + 4) = 0
x² - (-7/4 - 16/4)x + (-1/4 + 14/4 + 16/4) = 0
x² - (-23/4)x + (29/4) = 0
x² + 23/4x + 29/4 = 0
-------------------------------- × 4
4x² + 23x + 29 = 0