diketahui segitiga ABC dan alfa, beta, gama adalah sudut di A,B,C. jika diketahui sin beta=1/3 dan sin gama =1/2 maka BC/AC adalah...

sin Beta = sin B = 1/3 = de/mi => sa = √(3^2 - 1^2) = √(9 - 1) = √8 = 2√2
cos B = sa/mi = 2√2 / 3

sin gamma = sin C = 1/2 = de/mi => sa = √(2^2 - 1) = √(4 - 1) = √3
cos C = sa/mi = √3/2

A + B + C = 180°
A = 180° - (B + C)
sin A = sin (180° - (B + C))
= sin (B + C)
= sin B cos C + cos B sin C
= 1/3 . √3/2 + 2√2/3 . 1/2
= √3/6 + 2√2/6
= (√3 + 2√2)/6

BC/(sin A) = AC/(sin B)
BC/AC = (sin A)/(sin B) = ((√3 + 2√2)/6) / (1/3) = (√3 + 2√2)/2