jika f(x) = x2(x5-3x) maka f'(-1) = ......

semoga membantu ya.......

f(x)=x²(x^5-3x)=uv
f'(x)=u'v+v'u

u=x² u'=2x
v=x^5-3x v'=5x^4-3

f'(x)=2x*(x^5-3x)+(5x^4-3)*x²
f'(-1)=2(-1)*((-1)^5-3(-1))+(5(-1)^4-3)*(-1)²
=-2*(-1+3)+(5-3)*1
=-2*2+2*1
=-4+2
=-2

semoga bermanfaat:D