Batang korek api diletakan berdiri 20cm di depan cermin cekung tinggi korek api 4cm dan jarak titik api cermin 15cm.tentukan titik A.jarak bayangan B.pembesar b

a. jarak bayangan (s')
1/s' = 1/f - 1/s = 1/15 - 1/20 = 4/60 - 3/60 = 1/60
s' = 60 cm

b. perbesaran bayangan (M)
M = |s'/s| = |60/20| = 3x perbesaran

c. tinggi bayangan (h')
h' = M × h = 3 × 4cm = 12 cm

A. Jarak bayangan
1/f = 1/s + 1/s`
1/(15 cm) = 1/(20 cm) + 1/s`
1/s` = 1/(15 cm) - 1/(20 cm)
1/s` = 4/60 - 3/60
1/s` = 1/60
s` = 60/1 = 60 cm

B. pembesaran bayagan
m = s`/s
m = (60 cm) / (20 cm)
m = 3 cm

C. tinggi bayangan
s`/s = h`/h
(60 cm) / (20 cm) = h`/(4 cm)
h` = (60 cm) x (4 cm) / (20 cm)
h` = 12 cm