^a log (1/b) . ^b log (1/c) . ^c log (1/a) = tolong jawab secepatnya ya!!!

(alog(1/b) . blog(1/c)) . clog(1/a)
alog(1/c) . clog(1/a)
a log a = 1

alog(1/b).blog(1/c).clog(1/a)=
(^alog1-^alogb).(^blog1-blogc).(^clog1-cloga)
=(0-logb/loga).(0-logc/logb).(0-loga/logc)
=-(logb/loga).-(logc/logb).-(loga/logc)
= -1
semoga membantu