integral (x-3) (x²-6x+9)³ dx =
Matematika
Fita27
Pertanyaan
integral (x-3) (x²-6x+9)³ dx =
1 Jawaban
-
1. Jawaban idznizhahrina
U=x²-6x+9
du/dx=2x-6=2(x-3)
dx=du/(2(x-3))
Integral (x-3)u^3 du/(2(x-3))
=(1/2)(1/4)u^4 +c
=1/8 (x²-6x+9)^4 +c