Matematika

Pertanyaan

Nilai dari sin 270°.cos135°.tan210° per sin150°.cos225° adalah...

2 Jawaban

  • sin(180+90).cos(90+45).tan(180+30)/sin(90+60).cos(180+45)

    => -sin90.-sin45.tan30/cos60.-cos45

    => -sin90.tan30/cos60

    => -1 . 1/akar3 / 1/2
    => -2/akar3
    => -2/3 akar3
  • sin 270°.cos135°.tan210°/sin150°.cos225°
    =-sin90°.-cos45°.tan30°/sin30°.-cos45°
    =-1.-1/2√2.1 / 1/2.-1/2√2
    =1/2√2 / -1/4√2
    = -4/2
    =-2

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