bantu jawab pake cara ya,besok di kumpulin

0 < x < 2π

2 sin^2 x + sin x - 1 = 0 (misal sin x = y
2y^2 + y - 1 = 0
(2y - 1)(y + 1) = 0

@
2y - 1 = 0
2y = 1
y = 1/2
sin x = 1/2
x = 30 & 150

@
y + 1 = 0
y = - 1
sin x = - 1
x = 270

karena syaratnya 0 < x < 2π
maka, x = 30, 150, 270 = 1/6π, 5/6π, 3/2π