1.Jika f(x) = x^2 - 2x + 2 dan g(x) = x + 1 tentukan rumus fungsi (fog) (x) 2.diketahui f(x) = x^2 - x - 2 sedangkan g(x) = x + 3 nilai (fog) (-2) = 3.diketahui

1.
f(x) = x^2 - 2x + 2
g(x) = x + 1
fog(x) = f(g(x)) = (x+1)^2 - 2(x+1) + 2
= x^2 + 2x + 1 - 2x -2 + 2
= x^2 + 1

2.
f(x) = x^2 - x -2
g(x) = x + 3
fog(-2) = f(g(-2))
g(-2) = -2 + 3 = 1
f(g(-2)) = 1 - 2 + 2 = 1

3. integral
f(x) = 4 / 3x+6
f'(x) = 6x - 3 / -4

4. turunan
f(x) = 3x^2 + 5x -7
f(x) = 6x + 5

smoga membantu

1) (f o g)(x) = f(g(x))
= f(x + 1)
= (x + 1)^2 - 2(x + 1) + 2
= x^2 + 2x + 1 - 2x - 2 + 2
= x^2 + 1

2) g(x) = x + 3 => g(-2) = -2 + 3 = 1
f(x) = x^2 - x - 2
(f o g)(-2) = f(g(-2)) = f(1) = 1^2 - 1 - 2 = -2

3) f(x) = 4/(3x + 6)
4/(3x + 6) = y
3xy + 6y = 4
3xy = 4 - 6y
x = (4 - 6y)/3y
f^-1(x) = (4 - 6x)/3x

4) f(x) = 3x^2 + 5x - 7
f'(x) = 6x + 5