diketahui f(x) = 3x^2-5 dan g(x) = akar 2x-1, maka (fog)(x)

(fog)(x)=(3(akar2x-1)^2)-5
=(3(2x-1))-5
=6x-3-5
=6x-8

f(x) = 3x^2 - 5
g(x) = √(2x - 1)
(f o g)(x) = f(g(x))
= f(√(2x - 1))
= 3(√(2x - 1))^2 - 5
= 3(2x - 1) - 5
= 6x - 3 - 5
= 6x - 8