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Pertanyaan

Tentukan ph dari larutan 100ml NACN 0,2M dik ka=1*10-5

1 Jawaban

  • [OH-] = akar (Kw/Ka × Mgaram × valensi)
    [OH-] = akar (10^-14/10^-5 ×2 × 10^-1 × 1)
    [OH-] = akar (2 × 10^-10)
    [OH-] = 1.4 × log 10^-5
    pOH = 5 - log 1.4
    pH = 9 + log 1.4

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