fungsi f: R —> R didefinisikan sebagai f(x) = 5x-1/2x-3, x≠3/2. invers dari fungsi f adalah f^-1(x)= tolong banget di jawabb yg tauuu. besok ulangan soalnyaa ma

f(x) = (5x - 1)/(2x - 3)
(5x - 1)/(2x - 3) = y
2xy - 3y = 5x - 1
2xy - 5x = 3y - 1
x(2y - 5) = 3y - 1
x = (3y - 1)/(2y - 5)
f^-1(x) = (3x - 1)/(2x - 5) , x ≠ 5/2 ====> 2x - 5 ≠ 0 => 2x ≠ 5 => x ≠ 5/2

Cara lain :
f(x) = (ax + b)/(cx + d) => f^-1(x) = (-dx + b)/(cx - a)
f(x) = (5x - 1)/(2x - 3) => f^-1(x) = (3x - 1)/(2x - 5)

5x - 1 / 2x - 3 = y
5x - 1 = 2xy - 3y
5x - 2xy = 1 - 3y
x (5 - 2y) = 1 - 3y
x = 1 - 3y / 5 - 2y
f⁻¹(x) = 1 - 3x / 5 - 2x