luas segitiga jika di ketahui panjang sisi sinya 7cm 5cm dan 4cm adalah

7, 5, 4 bukan triple phytagoras

s = 1/2(7+5+4)
s = 1/2(16)
s = 8 cm
L = √s(s-a)(s-b)(s-c)
L = √8(8-7)(8-5)(8-4)
L = √8.1.3.4
L = √2³.1².1.3.2²
L = √1³.2^5.3
L = √1.32.3
L = √96 cm²

semoga membantu

Langsung aja y

a = 7 cm
b = 5 cm
c = 4 cm

s = ½ (a + b + c)
s = ½ (7 + 5 + 4)
s = ½ (16)
s = 8

L = √s(s-a)(s-b)(s-c)
L = √8 (8-7) (8 - 5) ( 8-4)
L = √8 × 1 × 3 × 4
L = √96
L = 4√6 cm²

Semoga berguna +_+