Mohon dijawab yaak yang benar saya kasih like dan 5 star deh 1. Diketahui f(x) = 5x - 6 dan gof (x) = -20x+27 maka g(x) adalah 2. diketahui g(x) = 2x+5 dan fog(

1) (g o f)(x) = -20x + 27
g(f(x)) = -20x + 27
g(5x - 6) = -20x + 27
Misal 5x - 6 = a => 5x = a + 6 => x = (a + 6)/5
g(a) = -20 (a + 6)/5 + 27
g(a) = -4(a + 6) + 27
g(a) = -4a - 24 + 27
g(x) = -4x + 3

2) (f o g)(x) = 8x + 17
f(g(x)) = 8x + 17
f(2x + 5) = 8x + 17
Misal 2x + 5 = a => 2x = a - 5 => x = (a - 5)/2
f(a) = 8(a - 5)/2 + 17
f(a) = 4(a - 5) + 17
f(a) = 4a - 20 + 17
f(x) = 4x - 3

3) sin a = 3/5 = de/mi => sa = √(5^2 - 3^2) = √(25 - 9) = √16 = 4
cos a = sa/mi = 4/5

4) cos a = 12/13 = sa/mi => de = √(13^2 - 12^2) = √(169 - 144) = √25 = 5
tan a = de/sa = 5/12

5) Tan a = 7/24 = de/sa => mi = √(7^2 + 24^2) = √(49 + 576) = √625 = 25
Sin a = de/mi = 7/25

de = sisi depan
sa = sisi samping
mi = sisi miring