fungsi f(x)=2x+1/x-3, x#3. jika f-¹ adalah invers fungsi f maka f-¹(x-2)= tolong jwb ya

y = (2x + 1)/(x - 3)
y(x - 3) = 2x + 1
xy - 3y = 2x + 1
xy - 2x = 3y + 1
x(y - 2) = 3y + 1
x = (3y + 1)/(y - 2)
f^-1(x) = (3x + 1)/(x - 2)
f^-1(x - 2) = (3(x - 2) + 1)/(x - 2 - 2)
= (3x - 6 + 1)/(x - 4)
= (3x - 5)/(x - 4)