Kak Tolong Di Bantu kak

[tex] \pi [/tex] x r x r 
luas lingkaran = 22/7 x 14 x 14 = 616cm^2
derajat = 45/360 = 1/ 8
luas juring = 616/8 = 77cm^2
sin 45 x 14= x
1/2√2 x 14 = x
7√2=x
luas segitiga = 7√2 x 7√2 x 1/2 = 98 x 1/2= 46
luas bagian yang diarsir = 77 - 46 = 31cm^2

[tex] \pi [/tex] x r xr
luas lingkaran = 22/7 x 14 x 14 = 616cm^2
derajat = 45/360 = 1/ 8
luas juring = 616/8 = 77cm^2
sin 45 x 14= x
1/2√2 x 14 = x
7√2=x
luas segitiga = 7√2 x 7√2 x 1/2 = 98 x 1/2= 49
luas bagian yang diarsir = 77 - 49 = 28cm^2