tolong di bantu di jawab no 1-5

1) x + 3 = 0
x = -3
f(-3) = 0
(-3)³ + m(-3)² + 59 = 0
-27 + 9m + 59 = 0
9m + 32 = 0
9m = -32
m = -32/9 = 3(5/9)

2) f(x) =(ax + b)/(cx + d) inversnya
f'(x) = (-dx + b)/(cx - a)
f'(x) = (6x + 4) / (5x - 3)

3) lim x --> ∞ (√ax²+bx+c - √ax²+px+q)
= (b - p)/2√a
jika dijabarkan jadi
lim x->∞ (√x²+(p+q)x+(pq) - √x²)
= (p+q) - 0 / 2√1
= (p+q) / 2

4) gof(x) = g(2x) = 5(2x) - 2 = 10x - 2

5) turunan > 0
3x² - 8x > 0
x(3x - 8) > 0
x < 0 atau x > 8/3