[tex] \lim_{x \to \infty} ( \sqrt{4 x^{2} +2x-4} - \sqrt{4 x^{2} -6x+3} =...[/tex]
Matematika
meuthianf
Pertanyaan
[tex] \lim_{x \to \infty} ( \sqrt{4 x^{2} +2x-4} - \sqrt{4 x^{2} -6x+3} =...[/tex]
1 Jawaban
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1. Jawaban whongaliem
[tex] \lim_{x \to \infty} \sqrt{4 x^{2} + 2x - 4} - \sqrt{4 x^{2} - 6x + 3} = ... =\ \textgreater \ a = 4 ; b = 2 ; p = - 6[/tex]
[tex]= \frac{b - p}{2 \sqrt{a} } [/tex]
[tex]= \frac{2 - ( - 6)}{2 \sqrt{4} } [/tex]
[tex]= \frac{2 + 6}{2 . 2} [/tex]
[tex]= \frac{8}{4} [/tex]
= 2