turunan pertama dari f(x)=4√2x³-3 adalah.....

f (x) = 4 √2x^3-3

misalkan :
u = 4 >>> u' = 1
v = √2x^3-3 = (2x^3-3)^1/2 >>> v' = 1/2 (2x^3-3)^-1/2

dy / dx = u'.v + u.v'
= 1 . (2x^3-3)^1/2 + 4 . {1/2 (2x^3-3)^-1/2}
= √2x^3-3 + 2 / √2x^3-3

semoga membantu :)