larutan garam dapur yang mengandung 1,17 g Nacl (Mr=58,5) tiap 100 mL larutan mempunyai konsentrasi?

M = gr/Mr x 1000/V
= 1.17/58.5 x 1000/100
= 0.02 x 10
= 0.2 M

Massa NaCl = 1,17 gram
Mr = 58,5
V = 100 mL = 0,1 L

n NaCl
= massa / Mr
= 1,17 / 58,5
= 0,02 mol


M = n/V
M = 0,02/0,1
M = 0,2 M