tolong bantu jawab please

EAC + BAC = 180°
127° + BAC = 180°
BAC = 53°

BAC + CBA + ACB = 180°
53° + 56° + ACB = 180°
ACB = 71°

a)
<ACB = 180* - 56* - (180*-127*)
<ACB = 124* - 53*
<ACB = 71*

b)
<D = 180* - (32*+(180*- 56) )
<D = 180* - (32* + 24*)
<D = 180* - 56*
<D = 124*

<CDF = 180* - 124*
<CDF = 56*