Mohon bantuanya teman teman beserta caranya.

A + B + C = D
(1 ... 0) + (8 ... 1) + (x ... -4) = (3y ... x)
(x .. -1) ... (3 .. y) .. (y ... -2) .. (2 .... -1)

(9 + x ................ -3) = (3y ... x)
(x + 3 + y ... -3 + y) .. (2 .... -1)

-3 = x

-3 + y = -1 => y = 2

x + 2y = -3 + 2(2) = -3 + 4 = 1