f(x) = (x2+1) (x3-1), maka turunannya adalah

Bab Differensial
Matematika SMA Kelas XI

f(x) = (x² + 1) (x^3 - 1)
f(x) = x^5 - x² + x^3 - 1
f'(x) = 5 . x^4 - 2x + 3 . x²
f'(x) = 5x^4 - 2x + 3x²
f'(x) = 5x^4 + 3x² - 2x

misal
u = x²+1
u' = 2x

v = x³-1
v' = 3x²

f'(x) = u'v + uv'
f'(x) = 2x(x³-1)+ (x²+1)(3x²)
f'(x) = 2x⁴-2x+3x⁴+3x²
f'(x) = 5x⁴+3x²-2x